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t^2+15=-36
We move all terms to the left:
t^2+15-(-36)=0
We add all the numbers together, and all the variables
t^2+51=0
a = 1; b = 0; c = +51;
Δ = b2-4ac
Δ = 02-4·1·51
Δ = -204
Delta is less than zero, so there is no solution for the equation
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